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2^2x=1/1024
We move all terms to the left:
2^2x-(1/1024)=0
We add all the numbers together, and all the variables
2^2x-(+1/1024)=0
We get rid of parentheses
2^2x-1/1024=0
We multiply all the terms by the denominator
2^2x*1024-1=0
Wy multiply elements
2048x^2-1=0
a = 2048; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·2048·(-1)
Δ = 8192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8192}=\sqrt{4096*2}=\sqrt{4096}*\sqrt{2}=64\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-64\sqrt{2}}{2*2048}=\frac{0-64\sqrt{2}}{4096} =-\frac{64\sqrt{2}}{4096} =-\frac{\sqrt{2}}{64} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+64\sqrt{2}}{2*2048}=\frac{0+64\sqrt{2}}{4096} =\frac{64\sqrt{2}}{4096} =\frac{\sqrt{2}}{64} $
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